Swift Optionals

Article by: Manish Methani

Published on: October 14, 2021 at 8:04am
3 min 11 sec read

Consider Optionals as a kind of "parcel". Before you "unwrap" it you won't know if it contains something or not. Optional in Swift is used to handle optional values. Sometimes values may be present, sometimes not. They are indicated using ? (question) mark after optional name.

Syntax :-

Optionals are indicated using ? at the end of variable type.

  /* Optional Integer declaration */ 
 var age: Int?

 /* Optional String declaration */ 
 var name: String?

Now consider this, one with Optional string

var name: String? = "Jazz"

Another one with a Non-Optional string

var name: String = "Jazz"

Though both versions Optional and Non-Optional look same but they are not. An optional String is not a String with some "optional" setting turned on. It's not a special variety of String. A String and an optional String are completely different types.

What is forced unwrapping?

Unwrapping of an optional value can be done by using ! (exclamation) mark at the end of variable type. Consider this example for better understanding of Forced Unwrapping

1) Before Unwrapping :-

import UIKit

var name:String?
name = "Manish"

if name != nil {
    print(name)
}else {
    print("Your Name has nil value")
}

Output :-

Optional("Manish")

2) After Unwrapping:

import UIKit

var name:String?

name = "Manish"

if name != nil {
/* Exclamation mark is added at the end */
    print(name!)
}else {
    print("Your Name has nil value")
}

Output :-

Manish

Automatic Unwrapping

To avoid using "!" mark at every optional variable , you can do this instead ,

var name:String!

Instead of using ? just declare ! mark at the time of declaration of an Optional variable. Simple and easy :)

Example of Automatic unwrapping:

import UIKit

/* Instead of writing ? mark, use ! mark for automatic unwrapping */
var name:String!
name = "Manish"
  if name != nil{
    print(name)
   }
  else 
   {
    print("Your Name has nil value")
   }